![]() ![]() It looks a little complicated when you read the explanation for the first time, but you'll get there, trust me. Everything else will work because of math, so just make sure to get this part right! Quick tip To make this trick work, you only have to put the main pile with the spectator’s card in the right position three times. Explaining the calculations – where to put the piles I’ve created a table down below with all the possible positions and where you have to put the main pile, but don’t worry – you can calculate it in a few steps as well. However, you have to know where to put the main pile as soon as the spectator calls out his number. The only thing you have to do when performing this trick is putting the main pile in the right position three times, and it will work. There are three options when putting the piles together, the main pile can be We’ll only focus on the pile with the spectator’s card, I’ll call it the “main pile” from now on. You achieve this by putting the pile with his card in the right spot three times. The spectator has chosen a number in the beginning, and you will control his card to this exact position in the deck. Once you know how to do the simple version, it’ll be a lot easier to understand this trick.īut let’s get to the interesting part now: how can you control the card to the right position in the deck?Ĭontrolling the spectator’s card to the right position (his chosen number) If this part is too fast for you, watch the video above or read my post about the easier version (the 21 card trick) by clicking this link. You can control his card to any position in the deck. The way you put the piles together defines the final position of the spectator’s card in the deck. ![]() Next, you put the three piles back together and repeat this two more times (create the three piles, ask the spectator to show the pile with his card, and put them back together). Once you are done, ask the spectator to show you the pile that has his chosen card in it (only the pile, not the card itself!). This is how I do it: Please note: There should be 9 cards per pile, this is just a photo from another card trick to show you how to spread the cards I’d recommend you to spread to cards a little bit so it’s easier to see them all. ![]() When your spectator has selected a card and a number, you have to create three piles with the cards facing up. Spreading the cards and creating the piles The spectator has chosen a card and a random number, and you will place the card in this exact position in the deck. It’s a free choice, so just ask him to pick anyone he likes and you can get started with the trick. The other thing you’ll need is a number between 1 and 27, which can be selected by the spectator. The deck can be shuffled anytime, you will still be able to find the chosen card. You can hand him the deck over, ask him to think of any card he likes and that’s it. When selecting the spectator’s card, you don’t have to do anything. You don’t need any preparation, you can really just count 27 cards from a deck and you are good to go. When learning the method, always make sure to count your cards correctly, it will only work with exactly 27 cards. My tutorial for the 27 card trick (step by step)Īll you need for the trick are 27 different cards, it doesn’t matter how they look, they just have to be different. But to be honest: he does a really good job explaining how it works, but it can be quite confusing if there is too much math at once.Īfter watching some videos about the trick, this is the one I liked the most: This trick was developed by the Mathematician Matt Parker who made this video, showcasing and explaining the entire card trick. I created a tutorial for “21 Card Trick” or the “Three Pile Card Trick”, you can find my post about this trick by clicking this link.īut with the “27 Card Trick”, the ending is way better because the spectator can choose a random number, and you will put his card in this position in the deck. It might be a good idea to check it out before learning the advanced version. It’s called the “21 Card Trick” and is based on the same principle, but it’s significantly easier to perform. ![]() This trick is based on math and therefore requires no sleight of hand, secret card counting, or any other sneaky moves.īefore I start with the explanation, I just want to point out that there is a simpler version of this trick. The 27 card trick explained: How it works ![]()
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